You will analyze solutions
made from recently recovered "Martian sedimentary carbonate rocks"
. You will determine their Mg-Ca
carbonate composition , information which may provide insight into the drying of the Martian landscape.
(Magnesium Carbonate is much more soluble than Calcium Carbonate)
To do this:
You will be given the mass of Carbonate rock dissolved and the
total volume and concentration of HCl used to dissolve it.
You will determine the amount of acid required to dissolve all the
carbonates by titrating the excess HCl with NaOH of known concentration
You will determine the total alkaline earth ions present by titration with
EDTA of known concentration.
From the above data
- You will make two
semi-independent calculations of the Ca-Mg carbonate ratio.
Carbonate dissolved = molCa(100.09) + molMg(167.9)
Moles of HCl used up = 2(molCa + molMg)
molCa + molMg = (VEDTA )(MEDTA)